330=3x^2

Solution for 330=3x^2 equation:

330=3x^2

We move all terms to the left:

330-(3x^2)=0

a = -3; b = 0; c = +330;
Δ = b2-4ac
Δ = 02-4·(-3)·330
Δ = 3960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3960}=\sqrt{36*110}=\sqrt{36}*\sqrt{110}=6\sqrt{110}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{110}}{2*-3}=\frac{0-6\sqrt{110}}{-6}
=-\frac{6\sqrt{110}}{-6}
=-\frac{\sqrt{110}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{110}}{2*-3}=\frac{0+6\sqrt{110}}{-6}
=\frac{6\sqrt{110}}{-6}
=\frac{\sqrt{110}}{-1}
$